5n^2+5n-2550=0

Solution for 5n^2+5n-2550=0 equation:

5n^2+5n-2550=0

a = 5; b = 5; c = -2550;
Δ = b2-4ac
Δ = 52-4·5·(-2550)
Δ = 51025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{51025}=\sqrt{25*2041}=\sqrt{25}*\sqrt{2041}=5\sqrt{2041}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{2041}}{2*5}=\frac{-5-5\sqrt{2041}}{10}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{2041}}{2*5}=\frac{-5+5\sqrt{2041}}{10}
$